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1 Find = 4 at x = 1 and y = x²5 Let x = (x 1,x 2,x 3), y = (y 1,y 2,y 3) ∈ R 3 Show that (x, y) = 10 x 1 y 1 3 x 1 y 2 3 x 2 y 1 2 x 2 y 2 x 2 y 3 x 3 y 2 x 3 y 3 is an inner product in R 3 (R) With respect to this inner product, find the angle between the vectors (1, 1, 1) and (2, − 5, 2) 6 Consider the set M n ×Free PreAlgebra, Algebra, Trigonometry, Calculus, Geometry, Statistics and Chemistry calculators stepbystep

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Y=4 x^2 y=2-x x=-1 x=1-Mar 22, 10lim x>1 1x^2/x^3x^2 which will be 0/0 so use L'Hopital lim x>1 2x/3x^22x which will become 2/1 = 2 Now suppose x = y^2, turning the problem into lim y>1 1y^3/y^5 y^3 Again, this is a 0/0 situation so L'Hopital to get lim y>1 1 3y^2/5y^4 3y^2 = 2/2 = 1 What can we conclude?Solution for 4x/y=2 (x1) equation x in (oooo) (4*x)/y = 2* (x1) // 2* (x1) (4*x)/y (2* (x1)) = 0 (4*x)/y2* (x1) = 0 (2*y* (x1))/y (4*x)/y = 0 4*x2*y* (x1) = 0 4*x2*x*y2*y = 0 4*x2

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Its thinnest point is where x 2 y = 12 = 1 Thus, Sis the portion of the surface z= p x2 y2 over the region D= f(x;y) 1 x2 y2 9g So ZZ S x2z2 dS = ZZ DSTAT 400 Joint Probability Distributions Fall 17 1 Let X and Y have the joint pdf f X, Y (x, y) = C x 2 y 3, 0 <1) is a critical point The second derivative test f xx = 2;f yy = 2;f xy = 0 shows this a local minimum with

Feb 28, 16By using Pythagoras you would end up with the equation given where the 4 is in fact r2 To obtain the plot points manipulate the equation as below Given x2 y2 = r2 → x2 y2 = 4 Subtract x2 from both sides giving y2 = 4 −x2 Take the square root of both sides y = √4 − x2 Now write it as y = ±Manipulate c in (x^2 x y y^2) 1 = c;Dec 16, 09If y = (1 x)(1 x^2)(1 x^4) (1 x^(2n) ), find dy/dx at x = 0 For any of the partial derivatives past the first quotient (1 x), you will have a derivative of 2nx^(2n1)

Contact Pro Premium Expert Support »Free System of Inequalities calculator Graph system of inequalities and find intersections stepbystepX, zero elsewhere a) What must the value of C be so that f X, Y (x, y) is a valid joint pdf?b) Find P (X Y <

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Example 5 X and Y are jointly continuous with joint pdf f(x,y) = (e−(xy) if 0 ≤ x, 0 ≤ y 0, otherwise Let Z = X/Y Find the pdf of Z The first thing we do is draw a picture of the support set (which in this case is the firstProfessionals For math, science, nutrition, history(c) ( y 2 x y 1 ) dx ( x 2 x y 1 ) dy = 0With M = y 2 x y 1 and N = x 2 x y 1, note that ( N x M y) / ( x M y N ) = ( x y ) / ( x ( y 2 x y 1 ) y ( x 2 x y 1 ) ) = ( x y ) / ( x y) = 1 Thus, μ = exp ( ∫ d(xy) ) = e xy is an integrating factor The transformed equation is ( y 2 x y 1 ) e xy dx ( x 2 x y 1 ) e xy dy = 0

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Aug 16, 11y=2x y=2x y=x2 xy=1 y=1x y=x1 Now to find the intersection of these two You could graph it or substitute the y for the other equation, then use the answer to solve for the other Lets replace the Ys y=x1 ;D ( x 2 y) D (y 4) = D ( 4 ) D ( 2x) , ( x 2 y' (2x) y) 4 y 3 y' = 0 2 , so that (Now solve for y' ) x 2 y' 4 y 3 y' = 2 2x y, (Factor out y' ) y' x 2 4 y 3 = 2 2x y, and (Equation 1) Thus, the slope of the graph (the slope of the line tangent to the graph) at (1, 1) is Since y'= 4/5 , the slope of the graph is 4/5N (R) of all real square matrices of

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8 Be careful in that our power series is now based at x 0 = 1 instead of x 0 = 0 xy00 y0 xy = x X1 n=2 n(n 1)a n(x 1)n 2 X1 n=1 na n(x 1)n 1 x X1 n=0 a n(x 1)n The problem is that we cannot incorporate x into a series with an (x 1) expansionWe know that $(x2y)(x2y)=4$ and that $(x2y)(x2y)=x^24y^2$ Thus, Quantity A MUST be equal to $4$, which is less than Quantity B The correct answer is B, Quantity B is greater What Did We Learn Coincidental mathematical relationships1)c) Let 0 <

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Tangent plane to (x^2 x y y^2) 1 at (x,y)=(1,2) SymmetricReduction((x^2 x y y^2) 1, {x^21, x}) (x^2 x y y^2) 1 >Simple and best practice solution for y=x1;y=2x4 Check how easy it is, to solve this system of equations and learn it for the future Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework If it's not what You are looking for type in the system of equations solver your own equations and let us solve itSubject to the constraint 2x2 (y 1)2 18 Solution We check for the critical points in the interior f x = 2x;f y = 2(y1) =)(0;

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Note that mathy'=\dfrac{x^2y^21}{x(2yx)}/math The substitution mathu=(2yx)^2/math transforms this to a linear DE math\begin{align*}u' &= 2(2yx)(2y'1Enjoy the videos and music you love, upload original content, and share it all with friends, family, and the world on YouTubeHave a question about using WolframAlpha?

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Thus, T is defined by the inequalities 0 <See the answer Show transcribed image text Expert Answer 100% (1 rating) Previous question Next question Transcribed Image Text from this Question y' = 2xy^2;Mar 10, 18#the equation of a line in color(blue)standard form# is #color(red)(bar(ul(color(white)(2/2)color(black)(AxBy=C)color(white)(2/2))))# #where A is

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1 Find P (Y <Solve by Substitution // Solve equation 2 for the variable y 2 y = 2x 1 // Plug this in for variable y in equation 1 1 (2x1) 4x = 3 1 2x = 4 // Solve equation 1 for the variable x 1 2x = 4 1 x = 2 // By now we know this much y = 2x1 x = 2Use your equation, y = x1 and choose an integer for x, say x=2, and substitute this into your equation to find the corresponding value of y y = 2 1 y = 1 So your first point has coordinates of (2, 1) Now repeat this operation with a different value of x, say x = 5 y = 5 1 y = 4 Your second point has coordinates (5, 4)

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Problem 10 () Sketch the region Dbetween y= x2 and y= x(1 x) Express Das a simple region and calculate the integral of f(x;y) = 2yover D Solution y= x2 y= x(1 x) (1=2;1=4) The region Dis both vertically simple and horizontally simple, but the bounds for yin terms of x1 Find P (X Y <Knowledgebase, relied on by millions of students &

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1 if dy dt = 1 dz 3 Find dt at (x, y) = (1, 3) and z2 = x²We actually have 2 functions, y = √ x (the top half of the parabola);SOLUTION 1 Begin with x3 y3 = 4 Differentiate both sides of the equation, getting D ( x3 y3 ) = D ( 4 ) , D ( x3 ) D ( y3 ) = D ( 4 ) , (Remember to use the chain rule on D ( y3 ) ) 3 x2 3 y2 y ' = 0 , so that (Now solve for y ' ) 3 y2 y ' = 3 x2 , and

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A X) d) Let a >WolframAlpha brings expertlevel knowledge and capabilities to the broadest possible range of people—spanning all professions and education levelsHere y=2x/(1x^2) Make sense So multiply both side by (1x^2) a quadritic equation will form in which cofficent of x^2 will be y and that of x will be 2 And constant will be 2 For x to be real D greater than or equal to zero So D=2^2–4y^2≥0 now Y^

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Oct 10, 07x^2 xy y^2 = (xy/2)^2 (3/4)y^2 Then your equation writes as (3/4)y^2 = 1 (xy/2)^2 Clearly, y has the largest value when (xy/2)=0 Then (3/4)y^2 = 1, or y =2/sqrt(3), The corresponding value of x is x=1/sqrt(3)Question Y' = 2xy^2;Compute answers using Wolfram's breakthrough technology &

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Substitute v = y x 1−2( y x)−( y x) 2 = 1 k 2 x 2 Multiply through by x 2 x 2 −2xy−y 2 = 1 k 2 We are nearly there it is nice to separate out y though!And y = −√ x (the bottom half of the parabola) Here is the curve y 2 = x It passes through (0, 0) and also (4,2) and (4,−2) Notice that we get 2 values of y for each value of x larger than 0 This isStack Exchange network consists of 176 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers Visit Stack Exchange

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If y = 2 x1, find y when 1 x = 1 2 x = 0 3 x =1 4 x =5 If x2 y = 5, find y when 5 x = 0 6 x = 1 7 x = 2 8 x =4 9 If 3 xy = 2, complete the table below 10 Copy this number plane and graph the line 3 xy = 2 p r e p q u i z 901 x y 2 –2 –2 2 4 –4 –4 4 x 0 1 2 y worked example A runner set off from a point and maintained a speedSolution To find the value of x, we simplify the following solution Taking the LCM of (x1)(x2)(x4) we find the value ofA Power consists of two parts, (((x^4y^4))/(x^22x1)*(x1)/(x^2y))/(xy)/(xy) Exponent and Base, We are going to learn to identify components of

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Y = 1/(4 X^2) This problem has been solved!X 2z2 dS, where Sis the part of the cone z2 = x2 y between the planes z= 1 and z= 3 The widest point of Sis at the intersection of the cone and the plane z= 3, where x2 y2 = 32 = 9;The graph of y=2^x is found by plotting some points like this x=2, y=2^(2)=1/4, (2,1/4) x=1, y=2^(1)=1/2, (1,1/2) x=0, y=2^0=1, (0,1) x=1, y=2^1=2, (1,2) x=2, y=2^2=4, (1,4) y=(1/2)^x1 can be written as y=2^(x)1 So your graph of y=2^x will be reflected about the yaxis because of the x It will also be shifted up vertically because

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In elementary algebra, the binomial theorem (or binomial expansion) describes the algebraic expansion of powers of a binomialAccording to the theorem, it is possible to expand the polynomial (x y) n into a sum involving terms of the form ax b y c, where the exponents b and c are nonnegative integers with b c = n, and the coefficient a of each term is a specific positiveGraph y=2(x2)^24 Find the properties of the given parabola Tap for more steps Use the vertex form, , to determine the values of , , and Since the value of is negative, the parabola opens down Opens Down Find the vertex Find , the distance from the vertex to the focusFree Parabola calculator Calculate parabola foci, vertices, axis and directrix stepbystep

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A X)e) Let 0 <Graph y=2(x1)^24 Find the properties of the given parabola Tap for more steps Use the vertex form, , to determine the values of , , and Since the value of is positive, the parabola opens up Opens Up Find the vertex Find , the distance from the vertex to the focus Tap for more steps2x = 3 x = 1 x = 4 2 2 x = 3/2 The xintercepts 3/2, 1, 4 New questions in Math huhu please help in the parallelogram given below find the values of x and y show your solution 29 As a Punong Barangay, what Criteria should you consider assessing Hon BacusPowerPoint presentation to ensure good quality of the delivery of pre

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Solution You can answer the problem by rewriting the equation first That is by using the properties of logarithm y = log(x 1/x) y = log((x^21)/x)2xy=1 Geometric figure Straight Line Slope = 2 xintercept = 1/2 = yintercept = 1/1 = Rearrange Rearrange the equation by subtracting what is to the right of the1 For every (x, y) in T, x y >

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